how to find x-intercept and y-intercept?
example: 2 x squared + 3 y squared = 18 .
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OpenStudy (anonymous):
first put x equals 0
OpenStudy (anonymous):
and substiute in th equation gives you
OpenStudy (anonymous):
3y^2 equals 18
OpenStudy (anonymous):
x-intercept means the point where curve crosses x axis so put y=0 in the given equation and find x intersept and for y intercept put x=0 to find the point where curve crosses y axis
OpenStudy (anonymous):
y^2 equals 6
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OpenStudy (anonymous):
ahh.. got it. :) thank you. ^_^
OpenStudy (anonymous):
ok gd
OpenStudy (anonymous):
this for y intercept
OpenStudy (anonymous):
and y equals 0 for the x intercept
OpenStudy (anonymous):
eh how about, y = x^2 - 3x + 2, what is the y-intercept?
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OpenStudy (anonymous):
2
OpenStudy (anonymous):
since x equals 0 and subs.
OpenStudy (anonymous):
ahh... got it again.. :)
eh how about, y = x^3 - 2x^2 + x - 2 , what is the x-intercept?
OpenStudy (anonymous):
x equals 2
OpenStudy (anonymous):
take y equals 0 first
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OpenStudy (anonymous):
x^3 - 2x^2 +x-2 equals zero then take common factor x^2
OpenStudy (anonymous):
x^2(x-2)+x-2 equals 0
OpenStudy (anonymous):
x^2 (x-2) + 1 (x-2) = 0 .
OpenStudy (anonymous):
take common x-2
OpenStudy (anonymous):
x^2 + 1 (x-2) = 0.
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OpenStudy (anonymous):
no (x-2)(x^2+1)
OpenStudy (anonymous):
ahh.. got it again. :) hihi.. thanks a lot. :)
eh, how about, how to know the symmetry of a function?