Question

Simplify the expression.
cos^2x+sin^2x/cot^2x-csc^2x

Answer 1

cot^2x-csc^2x=(cos^2x/sin^2x)-(1/sin^2x)
=(cos^2x-1)/sin^2x
=-(1-cos^2x)/sin^2x
cos^2x+sin^2x=1
also
1-cos^2x=sin^2x.
Does that help?

Answer 2

yes kind of but if I simplify it even further what would the final answere be?

Answer 3

would it be csc x? or -1 or 1 or sec x?

Answer 4

-(1-cos^2x)/sin^2x=?

Answer 5

cot x?

Answer 6

nope
1-cos^2x=sin^2x
so
-(1-cos^2x)/sin^2x=-sin^2x/sin^2x=-1
cos^2x+sin^2x=1

Answer 7

so its 1?

Answer 8

nope

Answer 9

check the sign

Answer 10

-1?

Answer 11

yup

Answer 12

ohhhh thank you so much:)

Answer 13

u r welcome:)

Answer 14

can you help with this? Factor the algebraic expression below in terms of a single trigonometric function.

csc 2x - 1

Answer 15

I am sry I'v gotta go nw. It's past midnight here

Answer 16

ok gn:)

Answer 17

gn:)