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Chemistry 23 Online
OpenStudy (anonymous):

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OpenStudy (wolfe8):

The lab should have given you specific instructions

OpenStudy (anonymous):

it did but I don't understand how to do it

OpenStudy (wolfe8):

Alright can you paste the procedures?

OpenStudy (wolfe8):

I can help but what exactly are you looking for? The number of moles of sugar or the molar mass of it?

OpenStudy (wolfe8):

Ok so since n=m/molar mass, to get mass, you multiply the number of moles with the molar mass.

OpenStudy (wolfe8):

Didn't you just say the moles of compound is 0.002828?

OpenStudy (wolfe8):

Sure. Well she showed you how to get the ratio mass of Na in NaCl. What ration would you like for sugar? As I said before, the number of moles is the mass of a substance divided by its molar mass.

OpenStudy (wolfe8):

ratio* sorry Hmmmm. Ah I see. So mole ratio of each element in sugar. So can you get me the chemical compound of sucrose?

OpenStudy (wolfe8):

Alright then for C it will be 12 the molar mass of C over the molar mass of the whole molecule times the number of moles. Does that make sense?

OpenStudy (wolfe8):

Sure. So the total mass of C is: 12(12)/12(12)+1(22)+16(11) * 0.002828

OpenStudy (anonymous):

@wolfe8

OpenStudy (anonymous):

@wolfe8 ??

OpenStudy (wolfe8):

Ah my bad I should have written it as 12(12)/(12(12)+1(22)+16(11)) * 0.002828 or\[\frac{ 12(12) }{ 12(12)+1(22)+16(11) } \times 0.002828\]

OpenStudy (anonymous):

so 342?

OpenStudy (anonymous):

wait no its 0.967176

OpenStudy (wolfe8):

No. Try again.

OpenStudy (wolfe8):

Still not right. Make sure you do multiplications first before addition.

OpenStudy (wolfe8):

Correct. And then you can do the same for H and O but use their masses on top. Can you do that?

OpenStudy (wolfe8):

What we did was \[\frac{ mass of element }{ mass of compound } \times moles\]

OpenStudy (wolfe8):

Well we did for C. What we did exactly was \[\frac{ mass ofC12 }{ mass ofC12H22O11}\times moles\]

OpenStudy (wolfe8):

I showed you how to do for C. You have to get for H and O now. Use the mass of them instead of C on top in that equation

OpenStudy (wolfe8):

...you want the mass of each element. Why would you combine them after finding each of them so hard? No you don't combine. You will have 3 different values.

OpenStudy (wolfe8):

...I don't understand. You said: lala2: @wolfe8 can you help me find the moles of each element of sucrose or table sugar??? This is what I'm showing you... I'm sorry but I don't get what you actually want. This is why I asked for the procedures on the lab. I'll have to stop here I have a headache now. Good luck.

OpenStudy (wolfe8):

OK I think what we did is the final answer. Just put that in. Do the same method for the others.

OpenStudy (anonymous):

this looks like fun

OpenStudy (anonymous):

can you help @msumner

OpenStudy (anonymous):

its 5

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

i said 5

OpenStudy (anonymous):

whats 5?

OpenStudy (anonymous):

what wolfe said is true

OpenStudy (anonymous):

could you show me the steps?

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