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Chemistry 11 Online
OpenStudy (nottim):

When solving for H3O+ with pH, how do i 'get' rid of log ('move it to the other side')

OpenStudy (anonymous):

forget about the log

OpenStudy (anonymous):

H3O+ = 10^-pH

OpenStudy (nottim):

equation "pH=-log[H3O+)

OpenStudy (nottim):

alright thanks

OpenStudy (anonymous):

this formula will always work H3O+ = 10^-pH

OpenStudy (wolfe8):

\[x = b ^{y}\] y is the logarithm of x to base b, and is written \[y = \log _{b}(x)\] Or just use \[\log ^{-1}\] on your calculator.

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