Question

Problem in comments

Answer 1

@zepdrix here it is(:

Answer 2

\[\Large\bf\sf \frac{-5(-2x)^3}{10x}\]That what it looks like? :o

Answer 3

yeah

Answer 4

Something important to keep in mind:
That 3 exponent is being applied to BOTH the x and the -2.
So when you cube each of those, what do you get?

Answer 5

\[-2^{3} and x ^{3}\]

Answer 6

\[\Large\bf\sf \frac{-5(-2)^3x^3}{10x}\]Mmmk multiply out the -2's

Answer 7

What do you mean multiply out the -2's?

Answer 8

\[\Large\bf\sf (-2)^3\quad=\quad (-2)(-2)(-2)\quad=\quad ?\]

Answer 9

oh its -8

Answer 10

\[\Large\bf\sf \frac{-5(-8)x^3}{10x}\]

Answer 11

Personally I like to separate the coefficients and the x's.. makes it easier to deal with them individually.\[\Large\bf\sf =\quad\frac{-5(-8)}{10}\cdot\frac{x^3}{x}\]

Answer 12

so then when I subtract the x^3 and the x i'll get x^2

Answer 13

k sounds good\[\Large\bf\sf \frac{-5(-8)}{10}\cdot x^2\]

Answer 14

okay, and after that?

Answer 15

So next simplify the coefficient in front of x^2.

Multiply out the numerator first, then do the division.

Answer 16

Mm ya good job!

Answer 17

Thank you so much! I really do appreciate it! I will be coming to you with any exponent stuff that I dont get if you dont mind

Answer 18

@zepdrix ^

Answer 19

:3