Problem in comments

Question

Problem in comments

ineedhelp10 · Answer

@zepdrix here it is(:

zepdrix · Answer

$$\Large\bf\sf \frac{-5(-2x)^3}{10x}$$That what it looks like? :o

ineedhelp10 · Answer

yeah

zepdrix · Answer

Something important to keep in mind:
That 3 exponent is being applied to BOTH the x and the -2.
So when you cube each of those, what do you get?

ineedhelp10 · Answer

$$-2^{3} and x ^{3}$$

zepdrix · Answer

$$\Large\bf\sf \frac{-5(-2)^3x^3}{10x}$$Mmmk multiply out the -2's

ineedhelp10 · Answer

What do you mean multiply out the -2's?

zepdrix · Answer

$$\Large\bf\sf (-2)^3\quad=\quad (-2)(-2)(-2)\quad=\quad ?$$

ineedhelp10 · Answer

oh its -8

zepdrix · Answer

$$\Large\bf\sf \frac{-5(-8)x^3}{10x}$$

zepdrix · Answer

Personally I like to separate the coefficients and the x's.. makes it easier to deal with them individually.$$\Large\bf\sf =\quad\frac{-5(-8)}{10}\cdot\frac{x^3}{x}$$

ineedhelp10 · Answer

so then when I subtract the x^3 and the x i'll get x^2

zepdrix · Answer

k sounds good$$\Large\bf\sf \frac{-5(-8)}{10}\cdot x^2$$

ineedhelp10 · Answer

okay, and after that?

zepdrix · Answer

So next simplify the coefficient in front of x^2.

Multiply out the numerator first, then do the division.

zepdrix · Answer

Mm ya good job!

ineedhelp10 · Answer

Thank you so much! I really do appreciate it! I will be coming to you with any exponent stuff that I dont get if you dont mind

ineedhelp10 · Answer

@zepdrix ^

zepdrix · Answer

:3