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Chemistry 12 Online
OpenStudy (anonymous):

Im really frusterated and neeeeed help!!!

OpenStudy (joannablackwelder):

Sure. So, for NaCl, I get the same thing for mass, molar mass, and moles of the compound.

OpenStudy (joannablackwelder):

But since in 1 NaCl there is 1 Na and 1 Cl, I get the same value for moles of each element as moles of the compound.

OpenStudy (joannablackwelder):

Then you use Avogadro's number to convert to atoms.

OpenStudy (anonymous):

does that make sense to you

OpenStudy (joannablackwelder):

No...

OpenStudy (anonymous):

ughh me neither!!! so how would you do the next one?

OpenStudy (joannablackwelder):

What you have so car looks good.

OpenStudy (joannablackwelder):

*far

OpenStudy (joannablackwelder):

What I would do to get moles of each element is: For 1 mole of the compound, you have 12 moles of C, 22 moles of H, and 11 moles of O.

OpenStudy (joannablackwelder):

Multiply.

OpenStudy (joannablackwelder):

Then to convert each to atoms, use Avogadro's number.

OpenStudy (anonymous):

so 2904 (6.02 x 10 ^23)

OpenStudy (joannablackwelder):

0.0339 moles of C, 0.0622 moles of H, and 0.0311 moles of O.

OpenStudy (joannablackwelder):

What does 2904 represent?

OpenStudy (anonymous):

I multiplied 12 22 and 11

OpenStudy (joannablackwelder):

I meant multiply the number of moles of the compound by the number of times each element occurs in the compound.

OpenStudy (anonymous):

what do you get?

OpenStudy (joannablackwelder):

You need to calculate the number of moles and atoms of each element separately.

OpenStudy (joannablackwelder):

2.04 x10^23 atoms of C, 3.75 x10^22 atoms of H, and 1.87x10^22 atoms of O.

OpenStudy (joannablackwelder):

Or sum the number of moles, then multiply by Avogadro's number to get total number of atoms.

OpenStudy (anonymous):

so I add 2.04 3.75 and 1.87

OpenStudy (joannablackwelder):

No, add 0.0339, 0.0622, and 0.0311.

OpenStudy (anonymous):

so 7.65744?

OpenStudy (joannablackwelder):

Sorry, my mistake. Atoms of C should be 2.04 x10^22.

OpenStudy (anonymous):

so that's not right

OpenStudy (joannablackwelder):

I made a typo. Atoms of C should be 2.04 x 10^22, not 2.04 x 10^23.

OpenStudy (anonymous):

what do you get for the final answer?

OpenStudy (anonymous):

im about to give up on this!

OpenStudy (joannablackwelder):

I summed up all the atoms of each element to get 7.66 x 10^22 atoms. I don't know if that is what you are looking for or no though.

OpenStudy (anonymous):

no its not, its supposed to be just one number

OpenStudy (joannablackwelder):

Then I can't help you.

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