Chemistry
12 Online
OpenStudy (anonymous):
Im really frusterated and neeeeed help!!!
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
Sure. So, for NaCl, I get the same thing for mass, molar mass, and moles of the compound.
OpenStudy (joannablackwelder):
But since in 1 NaCl there is 1 Na and 1 Cl, I get the same value for moles of each element as moles of the compound.
OpenStudy (joannablackwelder):
Then you use Avogadro's number to convert to atoms.
OpenStudy (anonymous):
does that make sense to you
OpenStudy (joannablackwelder):
No...
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ughh me neither!!! so how would you do the next one?
OpenStudy (joannablackwelder):
What you have so car looks good.
OpenStudy (joannablackwelder):
*far
OpenStudy (joannablackwelder):
What I would do to get moles of each element is:
For 1 mole of the compound, you have 12 moles of C, 22 moles of H, and 11 moles of O.
OpenStudy (joannablackwelder):
Multiply.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
Then to convert each to atoms, use Avogadro's number.
OpenStudy (anonymous):
so 2904 (6.02 x 10 ^23)
OpenStudy (joannablackwelder):
0.0339 moles of C, 0.0622 moles of H, and 0.0311 moles of O.
OpenStudy (joannablackwelder):
What does 2904 represent?
OpenStudy (anonymous):
I multiplied 12 22 and 11
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
I meant multiply the number of moles of the compound by the number of times each element occurs in the compound.
OpenStudy (anonymous):
what do you get?
OpenStudy (joannablackwelder):
You need to calculate the number of moles and atoms of each element separately.
OpenStudy (joannablackwelder):
2.04 x10^23 atoms of C, 3.75 x10^22 atoms of H, and 1.87x10^22 atoms of O.
OpenStudy (joannablackwelder):
Or sum the number of moles, then multiply by Avogadro's number to get total number of atoms.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so I add 2.04 3.75 and 1.87
OpenStudy (joannablackwelder):
No, add 0.0339, 0.0622, and 0.0311.
OpenStudy (anonymous):
so 7.65744?
OpenStudy (joannablackwelder):
Sorry, my mistake. Atoms of C should be 2.04 x10^22.
OpenStudy (anonymous):
so that's not right
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
I made a typo. Atoms of C should be 2.04 x 10^22, not 2.04 x 10^23.
OpenStudy (anonymous):
what do you get for the final answer?
OpenStudy (anonymous):
im about to give up on this!
OpenStudy (joannablackwelder):
I summed up all the atoms of each element to get 7.66 x 10^22 atoms. I don't know if that is what you are looking for or no though.
OpenStudy (anonymous):
no its not, its supposed to be just one number
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
Then I can't help you.