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Mathematics 22 Online
OpenStudy (anonymous):

Math Problem

OpenStudy (anonymous):

OpenStudy (anonymous):

anybody?

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (lastdaywork):

@collegekids Are the graphs part of the question or your solution ??

OpenStudy (anonymous):

no, they are simply there because nin requested them

OpenStudy (anonymous):

I got 1.45 miles as an answer

OpenStudy (lastdaywork):

What formula you used? Lets say - find the distance traveled in 10s.

OpenStudy (anonymous):

Im not entirely sure, I just found the average

OpenStudy (anonymous):

and added them together

OpenStudy (lastdaywork):

"...find the distance traveled in 10s..."

OpenStudy (anonymous):

Okay, here is what i did

OpenStudy (anonymous):

I added the average of the time to the speed and I got a total of 523.5

OpenStudy (anonymous):

I then divided that by 10

OpenStudy (anonymous):

multiplied by 100 and divided by 3600 for the number of seconds in an hour

OpenStudy (lastdaywork):

And your final answer is ________ miles ??

OpenStudy (anonymous):

1.45 miles

OpenStudy (lastdaywork):

You mean to say - distance traveled in 10s is 1.45 miles ??

OpenStudy (anonymous):

in 100 seconds

OpenStudy (anonymous):

They want you to do a Reimann Sum, using the midpoint for \(x_i^*\).

OpenStudy (anonymous):

The midpoint is n=5

OpenStudy (anonymous):

Basically remember that: \[ \Delta x = x_f - x_i = \int\limits_0^{100}v\;dt \approx \sum_{i=1}^n v(t_i^*)\Delta t \]And in this case: \[ t_i^* = \frac{t_i + t_{i-1}}{2} \]Also \[ \Delta t = \frac{b-a}{n} = \frac{100-0}{5} = 20 \]

OpenStudy (lastdaywork):

Well, I don't know what "Reimann Sum" or "midpoint rule" means (not good with terminology) When "acceleration is constant"; we use the formula average velocity = (initial velocity + final velocity)/2 See - http://openstudy.com/study#/updates/52ddf1cbe4b003c643a0f770 As the question is silent about the path through which the state is achieved; we can take acceleration to be constant for each interval. Hence distance traveled in each interval = Average velocity * Time period I think you can do the rest. :)

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