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Mathematics 16 Online
OpenStudy (anonymous):

Need help with a limit/integral problem http://puu.sh/6u228.jpg I have no clue what to do

OpenStudy (anonymous):

first expand

OpenStudy (anonymous):

then break up the summation in to three parts then pull the terms with n outside the sum, because the index is i not n

OpenStudy (anonymous):

can you show me? I'm new to this

OpenStudy (anonymous):

if the latex was working i could write it, but i cannot

OpenStudy (anonymous):

let me write in a document, and attach it

OpenStudy (anonymous):

although the first step, expanding, i am sure you can do i.e. compute (1 + 2i/n)(1+2i/n)

OpenStudy (anonymous):

give me a sec, i have to write the latex in a document, because i cannot write it here for some reason

OpenStudy (anonymous):

OpenStudy (anonymous):

this is kind of a pain to write like this, but the first steps are basic algebra everything without an i in it comes out of the summation now you can compute the limit one at a time

OpenStudy (anonymous):

sum 1 to n of 1 is just n as it is 1+ 1 + 1 + ... + 1 n times divide it by n and you get 1 for the first sum

OpenStudy (anonymous):

OpenStudy (anonymous):

last job is to take the limit as n goes to infinity, which is not hard if you think about it correctly

OpenStudy (anonymous):

the 1 stays a 1

OpenStudy (anonymous):

the second term is a polynomial of degree 2 divided by a polynomial of degree 2 limit is the ratio of the leading coefficients, which is this case is 4 / 2 = 2

OpenStudy (anonymous):

third term is a polynomial of degree 3 divided by a polynomial of degree 3, again the limit is the ratio of the leading coefficients

OpenStudy (anonymous):

hmm, so from what you've told me, the limit is 2?

OpenStudy (anonymous):

@satellite73

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