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OpenStudy (anonymous):
What is the oxidation number of B in H3BO3?
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OpenStudy (anonymous):
+3.... O is always -2 and there is 3 of them so that equals -6. H is always +1 and there are 3 of them so it equals +3. The compound has no charge on it which means it is neutral so the total of the oxidation numbers has to be 0. Therefore -6 + 3 + x =0. B is x, which equals 3
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