A 950 kg car is initially moving at 95 km/h. If the car is stopped in 6.50 s by a force of 3860 N opposite to the direction of motion, what is the stopping power of the cars breaks in watts?

Question

anonymous · Answer

Work done = force times distance
Power = work divided by time

You should work out the distance that the car stopped in.

Divide the force by the mass to get acceleration. Then you can use 
$d = ut-0.5at^2$ to get the distance

anonymous · Answer

yeah the distance is 4.063

anonymous · Answer

it never comes out right

anonymous · Answer

The distance is 85.7 m

Did you convert km/h to m/s?

anonymous · Answer

yeah

anonymous · Answer

The acceleration is 4.063 m/s^2, not the distance.

anonymous · Answer

ok yeah sorry thats what i meant ok finally got -85

anonymous · Answer

ah finally got it thanks