A particle of mass 83 g and charge 68 μC is
released from rest when it is 36 cm from a
second particle of charge −15 μC.
Determine the magnitude of the initial ac-
celeration of the 83 g particle.
Answer in units of m/s2

Question

A particle of mass 83 g and charge 68 μC is
released from rest when it is 36 cm from a
second particle of charge −15 μC.
Determine the magnitude of the initial ac-
celeration of the 83 g particle.
Answer in units of m/s2

anonymous · Answer

$$F = \frac{q_1q_2}{4\pi\epsilon_0r^2}$$

F is force, q is charge, $epsilon_0$ is vacuum permittivity 8.85 x 10^−12 F/m, r is the separation

Once you work out force (in N), divide the force by the mass (in kg) to get acceleration in m/s^2