Question

A circle has a radius of 8.5in . A sector of the circle has a central angle of pi/3 radians. Find the area of the sector.

Answer 1

@satellite73 can you please help me out a bit on this problem? thanks!

Answer 2

The formula for the area of a sector is\[A = \frac{ 1 }{ 2 }r ^{2}\theta\]
Where theta equals the value of the central angle in radians.
Replacing the values in this formula with those given, where r = 8.5 and theta = pi/3, we get:\[A = \frac{ 1 }{ 2 }(8.5)^{2}(\frac{ \Pi }{ 3 })\]

Answer 3

Calculating this gives us:
A = ?

Answer 4

ummm.... so you are saying ....

Answer 5

LOL
Which part of it didn't you get? xD

Answer 6

i'm sorry but i can't understand all the "A=fraq{(1)(2)" stuff can you use the equation buttons so that it can show it properly? Sorry for this confusion lol, but than you so very much for taking your time and helping me out.

Answer 7

thank*

Answer 8

No worries. LOL
I actually did use the equation thingy, but apparently it isn't working again. So I will type it out best as I can:

A = (1/2)(r)^2(theta)
A = (1/2)(8.5)^2(pi/3)

Answer 9

so this means A= 1/2 x r to the power of 2 x theta
and then plot in your numbers and get
A= 1/2 x 8.5 to the power of 2 x pi/3

Answer 10

Yup, that's correct. ^-^

Answer 11

that being said the answer would be 37.8!

Answer 12

And that would be correct too! xD

Answer 13

THANK YOU so much!!!! :)

Answer 14

You're welcome! :D