At what time has the car undergone a displacement of 12 meters? what is the car's velocity at that time? what is the car's acceleration at that time? Here is the picture... http://i.imgur.com/ZntWH.png For the bottom graph only please. thanks.

Question

At what time has the car undergone a displacement of 12 meters? what is the car's velocity at that time? what is the car's acceleration at that time? Here is the picture... http://i.imgur.com/ZntWH.png  For the bottom graph only please. thanks.

anonymous · Answer

For the first 4s, car is accelerating from 0 to 5 m/s, giving 
an acceleration of ( 5 m/s)/(4 s) = 1.25(1/2)(1.25) m/s^2

For constant acceleration, distance is
s=(1/2) (a) t^2
t = 1, s = (1/2) (1.25) (1)^2 = 0.625 m
t = 4  s = 1/2)(1.25)(4)^2 = 10.0 m

At the end of 4s, the car has gone 10m and is going 5 m/s.
Use this velocity to determine how long it takes to go the next 2m
to get to a total of 10m.

Look at the graph for that time and see whether the velocity is increasing (accelerating) or has become steady (a=0).

anonymous · Answer

Yes I am aware that the car has a displacement of 10m in 4s but not really quite sure how I would find it for 12m

anonymous · Answer

Nevermind I was able to figure it out. Thanks for the help.

anonymous · Answer

How do I find the car's velocity and acceleration at that time?

anonymous · Answer

@douglaswinslowcooper

anonymous · Answer

Congratulations.