I need help solving a few problems and then someone to help check a few answers-- please. Pictures in the reply (45-45-90 and 30-60-90 triangles)
@ranga
For the first problem, you need to find the hypotenuse in each right triangle and add them up. For the triangle on the left: cos(45) = adjacent / hypotenuse hypotenuse = adjacent / cos(45) = 52 / cos(45) = ? For the triangle on the right: hypotenuse = 98 / cos(30) = ? Add the two together.
I was told to use the Pythagorean theorem ???
You will get the same answer either way. For a 45-45-90 triangle: hypotenuse = sqrt(2) * any side = sqrt(2) * 52 = ? For a 30-60-90 triangle: hypotenuse = 2/sqrt(3) * long leg = 2/sqrt(3) * 98 = ?
im so lost.. is the hypotenuse 2704 because 52^2???
What do you get when you multiply: sqrt(2) * 52 =
73.5391052
Yes. How about 2/sqrt(3) * 98 ?
113.160653
Yes. Add the two numbers. Round your answer to the nearest tenth.
186.7 ?
Yes.
okay what about the next one?
They are asking for the side marked "x" in the diagram so we need to concern only with the 30-60-90 triangle. In a 30-60-90 triangle, the sides are in the ratio: 1:sqrt(3):2 The side opposite the 30 degrees is: 21 The side opposite the 60 degrees is: x 21:x = 1:sqrt(3) or x/21 = sqrt(3)/1 x = 21 * sqrt(3) =
36.373067?
then do I add 21?
36.373067 need to be rounded to the hundredth place. So it is 36.37 feet.
ohhh okay i understand. Next?
I will outline the method but you try to finish it because it uses the same principle as the previous two problems. The triangle on the right is a 30-60-90 triangle. The sides will be in the ratio 1:sqrt(3):2 Use the ratio to find AG. Then BA = BG - AG = 149 - AG (put from above calculation) The triangle on the left is a 45-45-90 triangle. The sides will be in the ratio sqrt(2)/2 : sqrt(2)/2 : 1 Use that ratio to find AC.
okay so BA = 64.9955358 CA= 91.9175682
AC*
Ok I just confused myself
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