Find the limit of the function algebraically. limit as x approaches two of quantity x^2-4/x-2 @agent0smith
First, try factoring the numerator.
I gotta go out for a bit, maybe @ranga can finish off.
OKAY :(
\[\huge\color{blue}{ \lim_{x \rightarrow 2}~~~\frac{x^2-4}{x-2} } \] \[\huge\color{blue}{ \lim_{x \rightarrow 2}~~~\frac{(x-2)(x+2)}{x-2} } \] cancel out x-2 and plug in 2 for x.
@agent0smith is it x+4
wait nooo
No
i have (x-2)(x+2)/x-2
Solomon: Are you using Chrome? The math editor, draw, latex, none of them work in Firefox for me.
\[\huge\color{blue}{ \lim_{x \rightarrow 2}~~~\frac{x^2-4}{x-2} } \] \[\huge\color{blue}{ \lim_{x \rightarrow 2}~~~\frac{(x-2)(x+2)}{x-2} } \] \[\huge\color{blue}{ \lim_{x \rightarrow 2}~~~\frac{\cancel{(x-2) }(x+2)}{\cancel{x-2 }} } \]
Solomon: All your replies are shown up raw.
\[\huge\color{blue}{ \lim_{x \rightarrow 2}~~~x+2}\] \[\huge\color{blue}{ \lim_{x \rightarrow 2}~~~\color{red} { 2 }+2}\] \[\huge\color{blue}{ \lim_{x \rightarrow 2}~~?}\] you tell me
@melacho, do you see the huge blue fractions, or a bunch of not making sense of letters numbers and etc ?
yes:/
ranga I am using chrome, and equation editor; yes. this is not a yes or no question....
do (x-2) and (x+2) cancel out?
No, only x-2 and x-2, not x+2 and x-2
so x+2
yes, you would then have limit x--->2 x+2 so plug in 2 for x, and you get limit x--->2 ? tell me the answer,
does not exist
I am not going to continue helping you, if you don't know how to plug in 2 for x. you are solving a limit and at this stage you should know this.
2^2-4/2-2=0/0
no no no, 1) factor the top. rule to use: a^2-b^2=(a+b)(a-b) 2) simplify the fraction, by canceling out (x-2) on top and bottom 3) plug in 2 for x.
4
no?
ok
Yes, 4, good job!
thanks c:
yw
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