Question

Gain a medal!
Find the horizontal or oblique asymptote of f(x) = -2x^2+3x+6/x+1
y=-1
y=-2
y=2x+3
y=-2+5

Answer 1

from the graph there are no horizontal asymptotes and there are no oblique asymptotes. there is a horizontal and parabolic asymptotes but no vertical or oblique asymptotes

Answer 2

which means what? Algebra really isn't my strong suit :p @habibmatatta

Answer 3

it means that the answer is that "there are no vertical or oblique asymptotes". thats the answer

Answer 4

That's not an answer choice.

Answer 5

plus, it was asking for horizontal; not vertical.

Answer 6

sorry there isn't a horizontal there is a vertical asymptote

Answer 7

-2 x^2+3 x+6 = (5-2 x) × (x+1)+1

So,

f(x) = (-2 x^2+3 x+6) / (x+1)
= (5-2 x) + 1/(x+1)

This equation has an oblique asymptote: 5 - 2x, because as x goes to infiity, the last term goes to zero.

As x goes to -1, f(x) goes to infinity, so there is a vertical asymptote at x=-1.

Answer 8

But @ybarrap she is looking for horizontal or oblique asymptotes

Answer 9

There is no horizontal asymptote, just vertical and oblique.

Answer 10

whats the oblique one. is it -2x^2+3x+1? thats what i got

Answer 11

5 - 2x is the oblique one