How can you solve ... ?

Question

calculusxy · Answer

$$4^{3}+4^{3}+4^{3}+4^{3}$$
Easily

amorfide · Answer

if you take out a factor of 4^3
you get 
4^3(1+1+1+1)
4^3(4)
4^4

calculusxy · Answer

What do you mean by "take out a factor"?

amorfide · Answer

Taking out a factor as in, what do they all have in common?

mertsj · Answer

3x^3+9y
Factor out 3

calculusxy · Answer

I don't get the "Factor out" thing. Can you more explain more?

amorfide · Answer

Taking out a factor, you want to take out what is common
so for
4x+2

what do they have in common? they can both be divided by 2
if you divide them by 2 you get 2x+1

what do you multiply 2x+1 by to get 4x+2?
you multiply by 2
so you get
2(2x+1)

in your case
4^3+4^3+4^3+4^3

they all are multiplied by 4^3
divide them all by 4^3
gives you
1+1+1+1
what is 1+1+1+1 multiplied by to give 
4^3+4^3+4^3+4^3
that is right, 4^3

so 4^3(1+1+1+1)
we know 1+1+1+1 is 4
4x4^3 is 4^4

anonymous · Answer

Divide by something that simplifies the expression, then use that at the beginning as a multiplier.

calculusxy · Answer

@amorfide Thank you.

amorfide · Answer

Anytime