Question

the equation x2+y2+ax+by+c=0 in standard form

Answer 1

x2+y2+ax+by+c=0
group the c terms and y terms separately and complete the squares:
(x^2 + ax) + (y^2 + by) + c = 0
complete the square for the terms inside the parenthesis.

Answer 2

can you show me?

Answer 3

(x^2 + ax) + (y^2 + by) + c = 0
{ (x + a/2)^2 - a^2/4 } + { (y + b/2)^2 - b^2/4 } + c = 0
(x + a/2)^2 - a^2/4 + (y + b/2)^2 - b^2/4 + c = 0
(x+a/2)^2 + (y+b/2)^2 - (a^2 + b^2 - 4c)/4 = 0
(x+a/2)^2 + (y+b/2)^2 = (a^2 + b^2 - 4c)/4
(x+a/2)^2 + (y+b/2)^2 = { sqrt((a^2 + b^2 - 4c))/2 }^2