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Mathematics 9 Online
OpenStudy (anonymous):

find the missing terms in each sequence 3, [?], [?], 20 (arithmetic)

OpenStudy (anonymous):

trial and error. 8.5 :DD

OpenStudy (anonymous):

that is the common difference by the way

OpenStudy (anonymous):

can i get the formula to find it, so i cant get it in my brain

OpenStudy (mathstudent55):

Let's say you have the following sequence: 2, 4, 6, 8 Obviously the common difference is 2, since that is the difference between any number and the previous number.

OpenStudy (anonymous):

there is two blanks between 3 and 20 so I cant get the common differnce

OpenStudy (mathstudent55):

We're working on that. be patient. Let's call the common difference d. The terms would be 2, 2 + d, 2 + 2d , 2 + 3d

OpenStudy (anonymous):

ok

OpenStudy (mathstudent55):

Now take the last term, 2 + 3d. Set that equal to 8. 2 + 3d = 8 Solve for d 3d = 6 d = 2 As you can see, we found the common difference in my example to be 2, which we already know is correct.

OpenStudy (mathstudent55):

Now try the same thing with your sequence.

OpenStudy (anonymous):

why did you set is equal to 8?

OpenStudy (anonymous):

u still there?

OpenStudy (mathstudent55):

In my example, the last term was 8. Now let's go back to your problem. 3, [?], [?], 20 3, 3 + d, 3 + 2d, 3 + 3d Notice that in your problem, 3 + 3d must equal 20. With that, you can write and solve and equation to find d. Once you know d, you can find the two middle terms.

OpenStudy (anonymous):

d = common difference if correct?

OpenStudy (mathstudent55):

Yes.

OpenStudy (anonymous):

d=5.6666

OpenStudy (mathstudent55):

Correct. Now you can find the two middle terms.

OpenStudy (anonymous):

thanks a ton

OpenStudy (mathstudent55):

You're welcome.

OpenStudy (anonymous):

ok ive got a pretty touch one : [?], [?], 2, [?], [?], 53.

OpenStudy (mathstudent55):

Pretend the sequence starts at the 2. Use the 2 and the 53 exactly like we did the problem and the example before.

OpenStudy (mathstudent55):

Then, once you find d, use d to find all missing terms.

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