Question

(-2)^4-3^2

Answer 1

7

Answer 2

7 is your answer

Answer 3

Yeah but how did you get it?

Answer 4

(-2)^4 - 3^2
=16-9
=7

Answer 5

-2^4 means 2x2x2x2 = 16
you have -2 and exponent of 4 then if the exponent is even then it will be positive but if add num then it will be negative so 16 remain
then 3x3 = 9

Answer 6

Oh I thought it would be a negative so I think that's why I was getting confused!

Answer 7

hint: when u have a negative base and ur going to an even power, the number will always be positive. if to an odd exponent, then the number will be negative

Answer 8

Could I get help with a few more?

Answer 9

sure

Answer 10

sure

Answer 11

\[\frac{ 5x ^{0} }{ y ^{-2} }\]

Answer 12

\( (-2)^4 = (-2) \times (-2) \times (-2) \times (-2) = 16\)

Answer 13

{5/y^2}

Answer 14

For the new problem:

\(a^{-n} = \dfrac{1}{a^n} \)

Change the negative exponent in the denominator into a fraction.

Answer 15

@mm2237 Not quite

Answer 16

anything raised to 0=1 and when u have a negative exponent, its like finding its recipricol so

5y^2

Answer 17

Also, \(x^0 = 1\)

Answer 18

Wait I forgot to mention x= 2 y= -3 z= -5 for these problems

Answer 19

so 5y^2, jsut substitute -3 for y

Answer 20

\(\Large \frac{ 5x ^{0} }{ y ^{-2} } = \frac{ 5 \cdot 1 }{ \frac{1}{y^2} } =
\frac{ 5 }{ \frac{1}{y^2} } = 5 \div \frac{1}{y^2} = 5 \times y^2 = 5y^2\)

Now substitute -3 for y:

\(5y^2 = 5(-3)^2 = 5(9) = 45\)

Answer 21

\[\frac{ 2x }{ y ^{2}z-1 }\]

Answer 22

so substitute

2(2)
--------
[(-3)^2 x -5]-1

Answer 23

so would it be \[\frac{ 2(2) }{ -3^{2}-5-1 }\] ?

Answer 24

and then \[\frac{ 4 }{ 6-6 }\] ?

Answer 25

-3^2 = 3x3 = 9

Answer 26

so

4
-----
(9x-5)-1

4
-----
-45-1

Answer 27

I'm confused, I already know the answer is -20/9 because that's what it says in the back of my text book I just don't know how they got it but this isn't all adding up to the same thing?

Answer 28

\(\dfrac{ 2x }{ y ^{2}z-1 } \)

\( =\dfrac{ 2(2) }{ (-3) ^{2}(-5)-1 } \)

\( =\dfrac{ 4 }{ 9(-5)-1 } \)

\( =\dfrac{ 4 }{ -45-1 } \)

\( =\dfrac{ 4 }{ -46 } \)

\( =-\dfrac{ 2 }{ 23 } \)

I don't know how you can get -20/9.