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if x and y are integers such that x^y=1, and xy=1, then y^x=? -1or 0 or 1 or 1.5 or 2
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Since xy = 1, neither x nor y can be zero.
x^y = 1, but y is not zero, so x must be 1.
Since x = 1, and xy = 1, y must be 1.
Therefore y^x = 1.
yes, x and y both are 1. I tried to solve it algebrically, using indices rules. thank u all
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mathstudent55, can u solve it algebrically?
Algebraically: Since xy = 1, x and y are reciprocals. Therefore, y = 1/x Substituting in x^y = 1, we get \( \Large x^{\frac{1}{x}} = 1 \) \( \Large \log x^{\frac{1}{x}} = \log 1 \) \( \Large \dfrac{1}{x} \log x = 0 \) \(\large \log x = 0\) \(\large x = 1\) Once you have x = 1, y = 1/x = 1/1 = 1.
thanks a lot.
You're welcome.
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