Question

Factoring help

Answer 1

shoot

Answer 2

wait a sec please

Answer 3

2x^2+x-6

Answer 4

(2x-3)(x+2)

Answer 5

2x^2+4x-3x+6
2x(x+2)-3(x+2)
(x+2)(2x-3)

Answer 6

Mizzz: Looks good. But "ineedhelp10" would no doubt appreciate your guidance in regard to HOW you came up with those factors.

MJB: Thanks for showing your steps. What's the name of this particular method of factoring?

Answer 7

@mjbmanny Where did you get the 2x(x+2) ?

Answer 8

look we got,
2x^2+4x=2x*x+2x*2
now take 2x common
2x(x+2)
got it?

Answer 9

find the factors for 6
it may be 6 and 1
3 and 2
trial and error my method

Answer 10

mjbmanny's method is known as "factoring by grouping," and he did a good job of demonstrating it.

Answer 11

I don't know where you got the 4x

Answer 12

mathmale, i donnt know any name of it but the trick that works for small equations with three terms and single varibale is this;
look for the term with middle degree, here the term with x in it
and calculate the product of the coefficients of remaining two terms
by trial and error, try to find the factors of the product that by addition or substraction make up the coffecient of the middle term. However, if the last term (the constant term) has a positive sign, the trick is to add the factors. But, if the last term has negative sign, then split the middle term by substracting two factors of the product mentioned before.
Easier method of understanding; just split the middle term appropriately.

Answer 13

above, i had x,
and 6*2=12 as the product of two remaining terms' coefficients
12 factors as 4*3 with 4-3=1.
so split x as 4x-3x.
the benefit of this is that if u get it right in the begining, there will certainly be factors; because already u have multiplied the coffiecients, found their multiple,and splitted the x by using those multiples.
it is called factoring by grouping allright.

Answer 14

I think you might of had conffused my problem

Answer 15

It was 2x^2+x-6

Answer 16

well, no i don't think so. let me show it again;

Answer 17

2x^2+x-6
split x as 4x-3x
2x^2+4x-3x-6
between 2x^2 adn 4x, 2x is common, between -3x and -6x, -3 is common
so lets separate the commons
2x(x+2)-3(x+2)
now lets again take (x+2) as common between these two terms,
(x+2)(2x-3). got it?

Answer 18

Thank you so much:)

Answer 19

you are welcome.