Question

sthyjdthadth

Answer 1

@radar @phi

Answer 2

@Mertsj

Answer 3

You need more information. Cannot solve one equation with two variables. Need 2 equations.

Answer 4

You should post the entire problem.

Answer 5

y=2/(x-x^2) we want to find any turning points for this graph. If the turning point is (h,k) the line y=k crosses the turning point in exactly one spot. So given the line y=k its intersection with the function would be from solving the system of equations with the equations being y=k and y=2/(x-x^2)

Answer 6

@Mertsj?

Answer 7

http://www.wolframalpha.com/input/?i=graph+y+%3D+2%2F%28x-x^2%29
That is the graph of your equation. It obviously has more than 1 turning point. I still think there is something wrong with your post.

Answer 8

ok thanks

Answer 9

yw

Answer 10

to get turning point , we put 1st derivative =0
y =2/(x-x^2)

find y'
and from y' = 0 , you will get 'x' values, which is your "h" in h,k
then you can find y from y =2/(x-x^2) which will be your "k"

Answer 11

ok thanks