Question

6 stools and 4 chairs cost $58 but 5 stools and 2 chairs cost $35. find the cost of each stool and each chair.

Answer 1

Your question is a case of linear equations in 2 variables.

Let the no. of stools be x, and chairs be y.

6x + 4y = 58
5x + 2y = 35

Use the elimination method or substitution method, whichever you like.

I will use elimination.

Multiply equation 2 by 2

You now have:

6x + 4y = 58
10x + 4y = 70

SUBTRACT. You now have

-4x + 0 = -12
4x = 12
x = 12/4 = 3

Substitute (x = 3) in the first equation.

6(3) + 4y = 58
18 + 4y = 58
4y = 58 - 18 = 40
y = 40/4 = 10

Therefore, each stool (x) costs $3 and each chair (y) costs $10.

Hope this helps.

Answer 2

thankyou so much....:)

Answer 3

anytime