Question

Much appreciated

Answer 1

Area is usually length times width, i think.

so my answer would be 272mm

Answer 2

your guess is as good as mine haha.

Answer 3

1/2 base by vertical height
as you dont have vertical height (only length of the legs)
maybe try Area of an isosceles triangle formula
A = ¼ ·b · √(4a^2 – b^2)
a = length of leg
b = length of base

Answer 4

so area in this case = 120... yeah?

Answer 5

seems legitimate ^^

Answer 6

k, so double pythag, and your equations above look fine to me hey

left triangle first, and yeah, x=20, perfect
h^2 = a^2 + b^2
25^2 = 15^2 + x^2
625 = 225 + x^2
625-225 = x^2
400 = x^2
x = 20

now right triangle,
h^2 = a^2 + b^2
y^2 = x^2 + 21^2
y^2 = 20^2 + 21^2
y^2 = 400 + 441
y^2 = 881
y = sqrt 881

Answer 7

sorry, my bad *841 not 881

Answer 8

fat fingers on the keyboard..., so y = sqrt 841

Answer 9

haha fat fingers

Answer 10

yep, sqrt is square root, so the tick symbol on ur calculator
ie sqrt of 16 = 4 as 4x4 = 16
in this case sqrt 841 = 29, as 29 x 29 = 841

Answer 11

so y = sqrt 841 = 29...

Answer 12

yep, but necessary simplyfing, as before we had:
y^2 = 841
so only way to get rid of y^2 is to sqrt it
sqrt y^2 = y
what we do to left side of equals sign we must do to right side
so Y^2 = 841
sqrt both sides
y = 29

Answer 13

Wow I understand, thank you so much for taking so much time to lend a hand I really appreciate it and the detail you went into thanks so much!

Answer 14

nah, anytime hey, my pleasure
slaters