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Mathematics 10 Online
OpenStudy (anonymous):

Please Help Will Medal!! I've gotten a few steps into this problem but need help finishing it. Find the area of a rectangle with a length of 2x+2/x-4 and a width of 3x-12/x^2+6x+5

OpenStudy (anonymous):

PLease Help Will Medal!! I've gotten a few steps into this problem but need help finishing it. Find the area of a rectangle with a length of 2x+2/x-4 and a width of 3x-12/x^2+6x+5

OpenStudy (anonymous):

@phi @Luigi0210 @douglaswinslowcooper @whpalmer4 Please help!

OpenStudy (whpalmer4):

I suggest that you factor the numerator and denominator of both fractions. Then when you multiply them together, there will be some common factors in the numerator and denominator which you can cancel to simplify.

OpenStudy (anonymous):

You can only factor the denominator in the second equation. You end up with the equations Length: 2x+2/x-4 and Width: 3x-12/(x+5)(x+1)

OpenStudy (whpalmer4):

you can also factor the numerator in both of them, look more carefully.

OpenStudy (anonymous):

None of the other x's are to a power. They only have a coefficient. To be able to factor they would have to be to a power.

OpenStudy (whpalmer4):

that's not true. you can 2x+2 as 2(x+1), for example

OpenStudy (anonymous):

So you mean factor out the coefficient. Okay

OpenStudy (whpalmer4):

yes, factor anything you can.

OpenStudy (anonymous):

Okay. so you end up with Length: x/x-4 Width: 3(x-4)/(x+5)(x+1)

OpenStudy (whpalmer4):

no... the length is (2x+2)/(x-4) that factors as 2(x+1)/(x-4)

OpenStudy (anonymous):

That's what I have written down. I must have messed it up typing it. okay. so whats' next?

OpenStudy (anonymous):

I know you multiply the two equations

OpenStudy (whpalmer4):

okay, write them out as a multiplication, then look for common factors to cancel 2(x+1) * 3(x-4) -------------- (x-4) * (x+5)(x+1)

OpenStudy (anonymous):

All of the symbols are the same so they wouldn't cancel out

OpenStudy (whpalmer4):

huh? let me reorder it for you 2*3*(x+1)*(x-4) -------------- (x+1)*(x-4)*(x+5)

OpenStudy (whpalmer4):

see any common factors in both numerator and denominator now?

OpenStudy (anonymous):

I see the (x+2) and (x-4) but the symbols aren't opposites so they don't cancel out

OpenStudy (whpalmer4):

what (x+2)? let me ask you another question. why is it that I keep asking you about factors canceling out if there really aren't any factors that cancel?

OpenStudy (whpalmer4):

if you have a common factor in both numerator and denominator, they cancel out: 6 -- 8 is the same as 2*3 ---- 2*4 the 2's cancel out, leaving you with 3 -- 4 we're doing exactly the same thing here.

OpenStudy (anonymous):

Pressed the wrong number. Sorry. I'm going back and forth between this and science. I meant (x+1)

OpenStudy (anonymous):

You'd end up with (2)(3)/(2+5)

OpenStudy (whpalmer4):

where are you getting (2+5)?!?

OpenStudy (anonymous):

I mean (x+5) on the bottom.

OpenStudy (whpalmer4):

you don't know the value of x

OpenStudy (whpalmer4):

okay, accuracy is important in math! 2*3 6 --- = ----- (x+5) (x+5)

OpenStudy (whpalmer4):

that's your final simplified answer

OpenStudy (anonymous):

That's the answer. Thank You!

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