Question

An arrow shot horizontally from a cliff at 15 m/s lands 30 m away. How how high is the cliff ?

Answer 1

Projectile motion in 2D (x,y plane) : It is fairly lengthy to derive these equations:

Answer 2

I cannot make an equation now...

Answer 3

x=( v cos alpha)t
y=(v sin alpha)t -1/2 g t^2

Where alpha is the angle you shoot the arrow.
v is the initial velocity
t is time
g is the universal gravitational constant

Answer 4

does it have to be so complex?

Answer 5

The answer for this question is 19.6cm height i dont know how to solve .

Answer 6

you need the right formula i think

Answer 7

There will be so many simplification as you are shooting the arrow horizontally.
Cos alpha=1
Sin alpha =0

Answer 8

x=vt
y=-1/2 g t^2

Answer 9

30=15 t
Thus t=2

Answer 10

y=-1/2 g 2^2=-2g=-2*9.80=-19.6

Answer 11

I am correct ?

Answer 12

Well you just had the solution :) And yes that is it

Answer 13

well done andras

Answer 14

Thanks for the help :)

Answer 15

Somehow I could not create proper equations, so it does not look so neat

Answer 16

Andras I am now your FAN :)

Answer 17

Yeah I lvld up :) 70 now

Answer 18

Hahaha :)

Answer 19

Andras the solution is correct ?