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You drop a rock off a bridge. The rock’s height, h (in feet above the water), after t seconds is modeled by h = -16t2 + 541. What is the height of the rock after 2 seconds? A. –64 feet B. 605 feet C. 509 feet D. 477 feet
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It's easy! Substitute 2 for (t) so h= -16(2)^2+541. Do parenthesis first and then exponents 2^2 = 4. h=-16(4)+541. Now do the multiplication -16*4= -64 h=-64+541...h = 477
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Sorry reading. Im dexlic
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Well, the answer is 477!
Thank you ^3^
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Anytime!
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