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Mathematics 13 Online
OpenStudy (anonymous):

Simplify the Expression

OpenStudy (anonymous):

sqrt(16x)+sqrt(x^5)

OpenStudy (anonymous):

I know the 16 is a perfect square and the square root of it is 4 so sqrt(16x)=4sqrt x but i don't know how to do sqrt (x^5) ?

OpenStudy (anonymous):

if sqrt(x^5) is simplified, can sqrt (x^4*x) correct?

OpenStudy (austinl):

\(\sqrt{16x}+\sqrt{x^5}\) \(\sqrt{16\times x}+\sqrt{x^4 \times x}\) Think you can try it from there?

OpenStudy (austinl):

Evidently latex isn't working.

OpenStudy (anonymous):

yeah i knew see what i did above, is it correct?

OpenStudy (austinl):

What is sqrt(x^4)?

OpenStudy (anonymous):

lol i tried to simplfy sqrt (x^5) into sqrt (x^4*x)

OpenStudy (austinl):

exactly, what is sqrt(x^4)? Hint, it does simplify down.

OpenStudy (anonymous):

oh it's x^2?

OpenStudy (austinl):

correct, so sqrt(x^5)=sqrt(x^4*x)=x^2*sqrt(x)

OpenStudy (anonymous):

ok thanks, i got it now :D!

OpenStudy (austinl):

Is that correct? :)

OpenStudy (anonymous):

yeah sqrt(16x)+sqrt(x^5) so sqrt(16x)=4sqrtx and sqrt x^5=sqrt(x^4*x)=x^2sqrtx 4sqrtx+x^2sqrtx is the answer! :)

OpenStudy (anonymous):

i forgot that i was dealing with sqrt x^4 and it's a perfect square

OpenStudy (anonymous):

thanks austin, you were a great help for me

OpenStudy (austinl):

No problem, glad to help! :D If you need anything else, feel free to ask :)

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