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Mathematics 11 Online
OpenStudy (anonymous):

gwhrwhy

OpenStudy (anonymous):

@phi

OpenStudy (anonymous):

i have the two pieces as x and 30-x. (1/3)x is the length of each side of the triangle and the length of each square side is (30-x)/4

OpenStudy (anonymous):

@RadEn

OpenStudy (phi):

so far so good. Now you need the formula for the combined area

OpenStudy (anonymous):

@phi i simplified it till (1/16)(x^2+(4x/sqrt3)-60x+900). i just don't know how to do -b/2a

OpenStudy (anonymous):

@phi?

OpenStudy (phi):

yes, you would use -b/2a but I don't believe your formula for the total area.

OpenStudy (anonymous):

what do you think it is then?

OpenStudy (phi):

area for an equilateral triangle is sqr(3)/4 * x^2 area of a square is x^2 (in this case (30-x)^2 )

OpenStudy (anonymous):

wouldn't the are of the square be ((30-x)/4)^2 because each side is 30-x/4? 30-x is the total length of the second piece of string

OpenStudy (phi):

yes, ( (30-x)/4 )^2 for the square and sqr(3)/4 (x/3)^2 for the triangle.

OpenStudy (anonymous):

ok so what would the total are be then now?

OpenStudy (phi):

can you work it out ?

OpenStudy (anonymous):

i think give me a sec

OpenStudy (anonymous):

A=(1/6)((900-60 x+x^2+(4 x^2)/sqrt(3))?

OpenStudy (phi):

you mean 1/16 not 1/6 , right ? and x is the length of the string used to make the triangle. its side is x/3

OpenStudy (anonymous):

sorry yeah 1/16. yes the side is x/3

OpenStudy (phi):

the area of the triangle should be sqr(3)/4 * x^2/ 9 = sqr(3) x^2 / 36 (I would leave the sqr(3) up top)

OpenStudy (anonymous):

ok so what would the total area be now

OpenStudy (phi):

distribute the 1/16, and collect terms you want to write down the equation of a parabola in the form ax^2 + bx + c so you can find its vertex (= -b/(2a) )

OpenStudy (anonymous):

but isn't my equation wrong?

OpenStudy (phi):

start with A = 1/16(x^2 -60x + 900) + sqr(3) x^2 / 36

OpenStudy (anonymous):

ok so it's (1/16)x^2-15/4x+225/4+sqr(3)x^2/36

OpenStudy (phi):

you should combine the x^2 terms

OpenStudy (anonymous):

(x^2/16+x^2/(12 sqrt(3)))

OpenStudy (phi):

you want a coefficient in front of x^2 so you can use it in -b/(2a) maybe you should change everything to decimals?

OpenStudy (anonymous):

or i could do (1/16+1/12sqrt3)x^2 right?

OpenStudy (phi):

yes. so a = (1/16+1/12sqrt3) but you will need a calculator to find a decimal equivalent of that mess. I would answer with a decimal number, unless the question is multiply choice in a different format.

OpenStudy (anonymous):

ok sure. and b=-15/4?

OpenStudy (phi):

btw, most people leave square roots in the top of a fraction (and never in the bottom) (before the invention of calculators, dividing by a square root was *way hard* so people never left a square root in the bottom) and yes, b = -15/4

OpenStudy (anonymous):

ok so -b/2a=(60(4sqrt3-3))/13=18.13

OpenStudy (phi):

what did you get for a?

OpenStudy (anonymous):

a=a = (1/16+1/12sqrt3) and aslo i did it wrong. i for got the 2a part -b/2a=(30(4sqrt3-3))/13

OpenStudy (phi):

a should be (1/16 + sqr(3)/36)

OpenStudy (phi):

or (1/16 + 1/(12 sqr(3) ) )

OpenStudy (anonymous):

yeah thats what i did

OpenStudy (phi):

-b is 3.75

OpenStudy (phi):

the answer is not 18.03 or 9...

OpenStudy (anonymous):

ok but is my -b/2a=(30(4sqrt3-3))/13 correct?

OpenStudy (phi):

no

OpenStudy (anonymous):

then what should it be?

OpenStudy (phi):

You almost have the answer. Just focus and work on it.

OpenStudy (anonymous):

what am i doing wrong?

OpenStudy (anonymous):

at least tell me this

OpenStudy (anonymous):

@sourwing

OpenStudy (anonymous):

@jdoe0001 @campbell_st @robtobey

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