gwhrwhy
@phi
i have the two pieces as x and 30-x. (1/3)x is the length of each side of the triangle and the length of each square side is (30-x)/4
@RadEn
so far so good. Now you need the formula for the combined area
@phi i simplified it till (1/16)(x^2+(4x/sqrt3)-60x+900). i just don't know how to do -b/2a
@phi?
yes, you would use -b/2a but I don't believe your formula for the total area.
what do you think it is then?
area for an equilateral triangle is sqr(3)/4 * x^2 area of a square is x^2 (in this case (30-x)^2 )
wouldn't the are of the square be ((30-x)/4)^2 because each side is 30-x/4? 30-x is the total length of the second piece of string
yes, ( (30-x)/4 )^2 for the square and sqr(3)/4 (x/3)^2 for the triangle.
ok so what would the total are be then now?
can you work it out ?
i think give me a sec
A=(1/6)((900-60 x+x^2+(4 x^2)/sqrt(3))?
you mean 1/16 not 1/6 , right ? and x is the length of the string used to make the triangle. its side is x/3
sorry yeah 1/16. yes the side is x/3
the area of the triangle should be sqr(3)/4 * x^2/ 9 = sqr(3) x^2 / 36 (I would leave the sqr(3) up top)
ok so what would the total area be now
distribute the 1/16, and collect terms you want to write down the equation of a parabola in the form ax^2 + bx + c so you can find its vertex (= -b/(2a) )
but isn't my equation wrong?
start with A = 1/16(x^2 -60x + 900) + sqr(3) x^2 / 36
ok so it's (1/16)x^2-15/4x+225/4+sqr(3)x^2/36
you should combine the x^2 terms
(x^2/16+x^2/(12 sqrt(3)))
you want a coefficient in front of x^2 so you can use it in -b/(2a) maybe you should change everything to decimals?
or i could do (1/16+1/12sqrt3)x^2 right?
yes. so a = (1/16+1/12sqrt3) but you will need a calculator to find a decimal equivalent of that mess. I would answer with a decimal number, unless the question is multiply choice in a different format.
ok sure. and b=-15/4?
btw, most people leave square roots in the top of a fraction (and never in the bottom) (before the invention of calculators, dividing by a square root was *way hard* so people never left a square root in the bottom) and yes, b = -15/4
ok so -b/2a=(60(4sqrt3-3))/13=18.13
what did you get for a?
a=a = (1/16+1/12sqrt3) and aslo i did it wrong. i for got the 2a part -b/2a=(30(4sqrt3-3))/13
a should be (1/16 + sqr(3)/36)
or (1/16 + 1/(12 sqr(3) ) )
yeah thats what i did
-b is 3.75
the answer is not 18.03 or 9...
ok but is my -b/2a=(30(4sqrt3-3))/13 correct?
no
then what should it be?
You almost have the answer. Just focus and work on it.
what am i doing wrong?
at least tell me this
@sourwing
@jdoe0001 @campbell_st @robtobey
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