Question

Help with limits?

Answer 1

wouldn't that be equivalent to 5/t - 5/t because the square root becomes 1?

Answer 2

If you direct-sub?

Answer 3

I'm not sure as to "methods" of limits. Been a while. Just patterns at this point

Answer 4

Do you know L'hopital's Rule?

Answer 5

rewrite as

(5/t) * (-1 + 1/sqrt(1+t)) and then use L'Hopital

Answer 6

I know L'Hopital, but we can't use it.

Answer 7

So you were specifically told not to use L'Hopital's Rule?

Answer 8

there's no infinity/infinity or 0/0?

Answer 9

I got answer, but is it possible to solve it algebraically and not graphically?

Answer 10

yes, it is.

Answer 11

That's what I was going to say, find it graphically. But I'm sure there's an easier non-graphical way to do it, I'm trying to remember.

Answer 12

change sqrt(1+t) to sqrt((t + t^2)/t) and you should be able to use L'Hospital

Answer 13

first get the common denominator and then multiply both top and bottom by 5 + 5sqrt(t+1)

Answer 14

you'll be able to cancel the t's, leaving you with -5/2 as the limit

Answer 15

Thank you!