A tennis ball is thrown straight up with an inital speed of 22.5 m/s. It is caught at the same distance abovethe ground.
How high doe the ball rise?
Please show work.

Question

A tennis ball is thrown straight up with an inital speed of           22.5 m/s. It is caught at the same distance abovethe ground.
How  high doe the ball rise? 
Please show work.

anonymous · Answer

Max height is when the vertical speed reaches zero.
You can calculate the time it took to get to the top by working out t
9.8t = 22.5

With that you can solve
d = 22.5t - 4.9t^2

doc.brown · Answer

$$v^2=v_0^2+2a(y-y_0)$$$$0=v_0^2+2a(y-0)$$$$-v_0^2=2ay$$$$y=\frac{-v_0^2}{2a}$$