Question

A tennis ball is thrown straight up with an inital speed of 22.5 m/s. It is caught at the same distance abovethe ground.
How high doe the ball rise?
Please show work.

Answer 1

Max height is when the vertical speed reaches zero.
You can calculate the time it took to get to the top by working out t
9.8t = 22.5

With that you can solve
d = 22.5t - 4.9t^2

Answer 2

\[v^2=v_0^2+2a(y-y_0)\]\[0=v_0^2+2a(y-0)\]\[-v_0^2=2ay\]\[y=\frac{-v_0^2}{2a}\]