Ask your own question, for FREE!
Physics 15 Online
OpenStudy (anonymous):

!!! One Medal Question !!!

OpenStudy (anonymous):

go for it

OpenStudy (anonymous):

Look at the diagram: The pin is pressed into the leather with a force of 150 N. The top of the pin has an area of 50 mm squared. The point of the pin has an area of 0.1 mm squared. 1.What is the size of the force exerted by the point of the pin on the leather? ____N 2. Calculate the pressure exerted by the point of the pin. Give the units.

OpenStudy (anonymous):

P= F/A P= 150/ .00001

OpenStudy (anonymous):

so is p=f/a for one and p=150/.00001 for 2

OpenStudy (anonymous):

no P=f/a is the formula i might have converted the .1mm to meters wrong, i am currently occupied with my physics lab about thermodynamics

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

is this for question 1 or 2

OpenStudy (anonymous):

1

OpenStudy (anonymous):

@Vincent-Lyon.Fr

OpenStudy (anonymous):

does that mean i have to divide 150 N by 50 mm squared

OpenStudy (anonymous):

wait.... 1 has already been answered... it says 150 was being exerted

OpenStudy (doc.brown):

@Abarnett Get back to work!

OpenStudy (anonymous):

why? hahaha i am taking a break... i am typing calculations :P

OpenStudy (anonymous):

it says the point of pin #1 is poorly worded

OpenStudy (anonymous):

calculate the pressure exerted by the point of the pin. Give the units

OpenStudy (doc.brown):

Sometimes I spend more time on here answering questions that I do working on my own questions. I hope you could hear the humor in my comment.

OpenStudy (anonymous):

yes, yes i do

OpenStudy (anonymous):

XD

OpenStudy (doc.brown):

You have energy spread out over an area. At the top of the pin it is 50mm^2 and at the bottom it is taking that energy and spreading it out over a smaller area.

OpenStudy (anonymous):

?

OpenStudy (anonymous):

but how would you work out the pressure

OpenStudy (anonymous):

F1/A1 = F2/ A2

OpenStudy (anonymous):

i am confused

OpenStudy (anonymous):

how would you work it out easily

OpenStudy (anonymous):

@doc.brown

OpenStudy (doc.brown):

1. The force is 150N 2. The force is spread out over the top of the pin. 150N / 50mm^2 That means one square millimeter has a part of the force, you should say Newtons per square millimeter. The bottom of the pin has a smaller area but the same amount of force. So the force per square millimeter will be greater than the top. 150N / 0.1mm^2

OpenStudy (anonymous):

so i would need to 150N / 0.1mm^2 for the answer

OpenStudy (doc.brown):

Correct

OpenStudy (anonymous):

will it be 15,000

OpenStudy (anonymous):

thnx so much once again you have been a great help to me cyah later bye

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!