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OpenStudy (anonymous):
Balancing Practice:_Fe2O3+h2---->Fe+H2O
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OpenStudy (wolfe8):
Look at each elements you have on both sides.
OpenStudy (asib1214):
Fe2O3+3H2-----> 2Fe+3H2O
OpenStudy (anonymous):
Put a 2 behind the second Fe and a 3 behind both H,s so Fe203 ---/ 2Fe + 3h20, there are now an equal number of elements on each side.
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