Question

use the discriminant to determine the number of real - number solution for the equation:8x^2 + 8x +2 =0

Answer 1

i do not know how to do this please help me.

Answer 2

first, do you know what is the discriminant?

Answer 3

ok... so do you know the general quadratic formula..?

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

Answer 4

yap -b+- under square b^2 - 4ac/2a

Answer 5

please

Answer 6

hello

Answer 7

ok... so the conditions are

discriminant > 0 you have 2 unequal zeros... if its a perfect square the roots are
rational... e.g. x^2 + 5x + 6 = (x + 3)(x + 2)

discriminant = 0 you have 2 equal roots ...e.g. x^2 + 6x + 9 = (x +3)(x +3) =
(x +3)^2

and lastly

discriminant < 0 you have complex roots or unreal roots...

so in your question a = 8, b = 8 and c = 2

substitute them into the discriminant and see what you get... then compare it to the choices..

Answer 8

and use

Discriminant = b^2 - 4ac

Answer 9

and one thing you need to know... every quadratic has 2 solutions...

even though they may be equal.