Question

use the discriminant to determine the number of real-number solution for the equation: 8x^2+8x+2=0

Answer 1

please help me to do this.

Answer 2

The quadratic formula equation is: x = [-b ± sqrt(b^2 - 4ac)] / 2a

The discriminant is the term for sqrt(b^2-4ac)
Take your a, b, and c values from your equation and plug them into that.

Answer 3

a=8,b=8 and c=2

Answer 4

Yup, you got it.

Answer 5

after that please?

Answer 6

Plug those numbers into the discriminant formula.
sqrt(8^2-4(8)(2))

Answer 7

64 -64 =0

Answer 8

is it?

Answer 9

Actually I'm sorry I made a little mistake. The discriminant is JUST b^2-4ac, no square root involved. In this case it doesn't matter but in future problems it might...sorry about that.

Yes, the value of the discriminant = 0. So what does this tell us about the roots of the function? It's either two real roots, one real root, or two complex number roots.

Answer 10

it says ,only use the discriminant to determine the number of real-number solution for the equation.

Answer 11

so what is the solution then?

Answer 12

Real number solutions equals roots, or zeros. Your solution is either 1 or 2, I was just explaining a little more as to whether they're real or imaginary.

Answer 13

ok

Answer 14

For this question the answer is one real root, because if you were to do the entire quadratic equation out you would get 2 x-values but it'd really be one value repeated.

Answer 15

please can you show me how it would be?

Answer 16

thanks you

Answer 17

I'm waiting you