how would you calculate the molecular weight of a compound if 4.00g of it plus 50.0 grams of water give a solution with a boiling point of 100.41 C the molal boiling constant for water is 0.52 C x kg.mol ? how would you do this ? IM STUCKKK HELPPPP
dT=i*m*Kb dT= change in temp i=van't off constant (i guess assume it to be 1 because they don't tell you the compound dissociates) m=molality Kb=molal boiling point constant
is it like this one ΔTB=KBm @aaronq
yep its the same thing
0.52 C x kg.mol x ____ = 100.41?
no, it's the change in temperature FROM the normal boiling temp, so: (0.52 C kg.mol)*m = 0.41
from there you can find the moles, then the molecular mass
0.41?
dT=NEW BP- NORMAL BP= 100.41-100 = 0.41
wait why would you take out the 100? @aaronq
because the formula uses the change (represented by Δ) in boiling point temperature (caused the solute). So you need to use only the change
how would you know that the change is
you would find the difference between the new boiling point temp from the normal (without solute) bp. dT=NEW BP- NORMAL BP= 100.41-100 = 0.41
i just don't understand how to find the normal BP
the normal boiling point of water is 100 degrees celsius
so 0.788462 moles/kg os solvent so 0.788462 x (molar mass of H2o? )/mole = 14.2044
?
nope, what did you get from the equation above for molality?
uh isn't molality moles of solute/ kg of solvent so 0.788426m is it not?
yep thats right, why are you using the molecular mass of water if it's in kg? it should be 0.788426m = n/0.05 kg
n=0.039421? do you add that to the 4.00 grams?
nope, the formula for moles is n=m/M so 0.039421=4g/M
wait what des n m and M stand for?
n = moles, m = mass, M= molar mass
so the Molar mass is 0.009855?
M=4 g/0.039421= 101.4687603054209685 g/mol
oh whoops THANKS this finally makes sense tytytyty
good stuff! no problem
0.788426m = n/0.05 kg why would you set up the equation like this though @aaronq
WAIT ACTUALLY JK I GOT IT
haha it just the definition of molality
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