Question

calculus 2

Answer 1

Hmm well the first one shouldn't be too tough.

I(0), plug 0 in for x.

So the integral of f(t) from 0 to 0.

Answer 2

2?

Answer 3

Integral is the area under the curve of the function.
If we think of it in terms of a ... rectangle.

Then imagine a rectangle with some height (let's not try to calculate it)
and ZERO width ( since we're integrating from 0 to 0) .

What would be the area of that rectangle, height x width.

Answer 4

0

Answer 5

good good.

Answer 6

I can't seem to figure out how they want us to calculate the other ones though.. hmmm

Answer 7

Numerical integration would be one approach. A Texas Instruments calculator can be programmed to find the area under a given curve from x=a to x=b using the built-in function fnInt(, whose arguments would be f(x), x, a, b, followed by a closing right parenthesis.

Answer 8

I(0)=0; I(.5)=1.00620; I(1.0)=2.17885; and so on.

Answer 9

thank you. my calculator can't do this though. Any other way to find the answers?

Answer 10

@mathmale do you have the last 2 values?

Answer 11

Wolfram can give them to you.
http://www.wolframalpha.com/input/?i=integral+of+2%28t%5E4%2B1%29%5E%281%2F2%29dt+from+t%3D0+to+t%3Dx

In the text box at the top, change the x to whatever value you need.
for example:
t=0 to t=1.5

Answer 12

Got them, thank you

Answer 13

Cool, cool, cool! Thanks, zepdrix.