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How do I find the radius of a sector formed on a circle of central angle 1/4 radians and area 6 square inches?
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well the area of the sector formula is \[A = \frac{\theta}{2} \times r^2\] where theta is the sector angle.. so substituting you have \[6 = \frac{\frac{\pi}{4}}{2} \times r^2\] just solve for r
Okay, this is what I have right now: 6=1/2(2pie/4)(r^2)
oops my mistake the angle says 1/4 radians.... i read it as pi/4 so 6 = 1/2 x 1/4 times r^2 so 6 = 1/8 r^2 or r^2 = 48 solve for r...
Okay if I did it correctly r is 4 root 3
yes that would be correct
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