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OpenStudy (anonymous):
OpenStudy (mathmale):
First of all, I notice that F'(t) can easily be integrated (which produces a constant of integration, C). It may be easiest to simply perform this integration, find C, and then evaluate F(t) for each of the given t values.
OpenStudy (mathmale):
You could paraphrase that to "evaluate F(b) for each of the given b values."
OpenStudy (mathmale):
Tachi: please integrate:\[\int\limits_{}^{}\sin t \cos t dt\]
OpenStudy (mathmale):
Hint: use a simple substitution.
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OpenStudy (anonymous):
i can't see the equation. can you post in a pic?
OpenStudy (raffle_snaffle):
let u=... Simple u sub.
OpenStudy (mathmale):
I'd love to post a pic, but the Draw utility is not currently functioning.
Go ahead, raffle_snaffle: propose the actual substitution you have in mind.
OpenStudy (anonymous):
Sry, I'm not sure what to do. We haven't gotten to U substitution yet
ganeshie8 (ganeshie8):
use advanced guessing
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ganeshie8 (ganeshie8):
before that simplify, sint cost to 1/2 sin(2t)
ganeshie8 (ganeshie8):
we knw that derivative of -cos is sin.
having known that, clearly the integral of sin(2t) will have a -cos(2t) term.
ganeshie8 (ganeshie8):
next, fix it be thinking a bit more.. :
does derivative of -cos(2t) give u sin(2t) ?
no, it gives u sin(2t) * 2,
so u need to divide by 2
ganeshie8 (ganeshie8):
overall :
integral sin t cos t dt
integral 1/2 sin(2t) dt
1/2 integral sin(2t) dt
1/2 [-cos(2t)]/2 + C
-1/4 cos(2t) + C
ganeshie8 (ganeshie8):
plugin the given point, and find C
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OpenStudy (anonymous):
Plug in 13?
OpenStudy (anonymous):
@ganeshie8
ganeshie8 (ganeshie8):
we got F(t) = -1/4cos(2t) + C
ganeshie8 (ganeshie8):
and we're given F(0) = 13
ganeshie8 (ganeshie8):
plugin t = 0 :)
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