Question

Help please!!! medals will be given :)

The function below shows the number of car owners f(t), in thousand, in a city in different years t:

f(t) = 1.1t2 - 2.5t + 1.5

The average rate of change of f(t) from t = 3 to t = 5 is ______ thousand per year.

Numerical Answers Expected!

Answer 1

differenciate the function and then put 5 and 3 in place of x

Answer 2

So what would it be? I don't really get it

Answer 3

@random231

Answer 4

rate of change = 2.2t-2.5.
when t=5
rate = 2.2*5 - 2.5
when t =3
rate= 2.2*3-2.5
so avg = ((2.2*5-2.5)+(2.2*3-2.5))/2

Answer 5

So for the avg what do i do?

Answer 6

avg = ((2.2*5-2.5)+(2.2*3-2.5))/2

Answer 7

calculate this

Answer 8

So it would be 6.3?

Answer 9

yea

Answer 10

alright thank you so much! Do you mind helping me with one more?

Answer 11

ure welcome