Question

The surface area of two similar figures are given. The volume of the larger figure is given. Find the volume of the smaller figure.


S.A. = 18 in2

S.A. = 98 in2

V = 343 in3

Answer 1

help please

Answer 2

:(

Answer 3

First, I'd choose a particular, simple figure to make the work easier for myself to understand. Why don't we assume that the figure is a cube? Hard to think of a figure simpler than that.

The volume of a cube is V=x^3, where x is the length of one of the sides.
The surface area of a cube is S=6x^2.

Thus, if the volume of our cube is 729, 729=x^3 and x=9.
Thus, each edge of the cube is 9.
The surface area of this cube would be S=6(9)^2, or 6(81), or 486.

Supposing the surface area of a smaller cube were 384, what would the volume of this cube be? First, I'd find the length of a side; that would come from solving the equation

6s^2=384 for s. 384/6 = 64. So s^2=64 and s=8. The volume of the smaller cube would then be s^3, or 8^3, or 512.

This was the first approach that came to mind.

There might be a much simpler way to address this problem, based on the fact that the two figures are "similar."

Hope this at least helps you to get started.

Answer 4

thanks!:) can you help me with another one?

Answer 5

The volumes of two similar figures are given. The surface area of the smaller figure is given. Find the surface area of the larger figure.

V = 27 in3

V = 125 in3

S.A. = 63 in2

Answer 6

I would like very much to help you with the 2nd problem, but if you read what I typed earlier, you'd see that I myself am not sure that my approach is valid. My suggestion is that you look through whatever study materials you have in your possession or could access online in search of an example problem for this topic.

Answer 7

No I got it now. I just finished reading what you typedme. Thanks:)I totally get it now

Answer 8

Its okay