Question

Given: ∠BCD ≅ ∠EDC and ∠BDC ≅ ∠ECD Prove: Δ BCD ≅ Δ EDC

Please help.

Answer 1

is there a picture that goes along with this? :)

Answer 2

alright :) gimme a sec then

Answer 3

<BCD = <EDC (Given)
CD = CD (Reflexive Property of Equality)
<BDC = <ECD (Given)
Δ BCD ≅ Δ EDC ASA

Answer 4

thank you! is there any way you can help on a few more? you laid it out in a way that actually made sense. :)

Answer 5

glad I could help :) and sure! :D

Answer 6

awesome! let me pull up the other questions :)

Answer 7

Given:D is the midpoint of AC, <BDC is congruent <BDA.Prove triangleABD is congruent triangleCBD

Answer 8

D is the midpoint of AC (Given)
AD = DC (Definition of Midpoint)
<BDC = <BDA (Given)
BD = BD (Reflexive Property of Equality)
triangle ABD = triangle CBD (SAS)

Answer 9

thank you!!! sorry for not replying my mom needed help with something! I only have 2 more questions and I am really dumb, if you don't want to help thats fine though!

Answer 10

lol it's fine ;)
I'm here to help, ask away!

Answer 11

Given: PG is congruent SG and PT is congruent ST . Prove: angle GPT is congruent angle GST

Answer 12

PG = SG (Given)
PT = ST (Given)
GT = GT (Reflexive Property of Equality)
triangle GPT = triangle GST (SSS)

Answer 13

awesome! ok last one :) thanks for being so awesome lol

Answer 14

Given: AB // CD , <B is congruent <D and BF is congruent ED . Prove: triangle ABF is congruent triangle CED

Answer 15

AB // CD (Given)
<FAB = <ECD (Alternate interior angles are congruent)
<B = <D (Given)
BF = ED (Given)
triangle ABF = triangle CED (AAS)

Answer 16

thank you so much :)

Answer 17

Your welcome :)
Best of Luck for your journey on OpenStudy!