I need help factoring this and i already know the roots are (x+3) and (x+2) 2. Factor f(x) = x4 + x3 – 8x2 + 6x + 36 completely. Then sketch the graph.
also how do i graph it?
Are you meant to use the remainder and factor theorems?
i do use the remainder but i used synth. div. to get -2,0 and -3,0
If so, then you try the positive and negative multiples of your constant, which would be 36. So your options are: 0, -1, +1, -2, +2, -3, +3 etc.
Well (x+2) is a factor. Then you use -2 in synthetic division and get...
x^3 - x^2 -6x +18
the remainder that would be 0
Repeat the process and you'll find the last root--one must not factor since there are only two roots in the ANS.
If the remainder is 0, you've found a factor.
ok im lost
Have you learned the remainder theorem and the factor theorem?
i learned the remainder theorem the factor theorm i dont know
If you plug a value into a function, f(x), and the y value you calculate is 0, then that point must lie on the x-axis. By definition, you are finding the "factors" of the function in doing so. As well as that, you are finding the x-intercepts.
If your remainder is 0, you have yourself a factor. The remainder theorem and the factor theorem are said to go hand-in-hand.
@Kinzan i just looked at the lesson again i used synth. div. to get the first 2 points you was saying to find the integers and graph them right? if that is correct then i just need you to walk me trough how to factor it before i use div.
The integers?
Well I used factor theorem. Using positive and negatives of the multiples of the constant of the function, which was 36, and plugged those values into x.
Whichever resulted in a remainder of 0 was a factor.
Use the number of the x-value that resulted in a remainder of 0 in your synthetic division.
ok so after i use foil i should have (x+3) (x+2) (x^2 + 5x + 6) this should be the factored form of the equation?
What are you foiling?
x+3 and x+2 when i use synth div. they become -3 and -2
Sure, okay. Then you used those values to generate the co-efficients for the next steps, right? I'm assuming so.
how do i do that i just tried to graph it and the graph is incorrect
The leading coefficient is positive and the degree is even, so the graph of this function opens upwards, and its end behaviour is similar to a parabola opening upwards. You have two x-intercepts if you have two roots.
Your y-intercept is (0, 36).
Sketch the graph now, is it correct?
sorry, im still lost here im confused, i already know what the factored form of the problem is how do i get the points on the graph
Your factors are your x-intercepts...you know your y-intercept as well.
factors are -2 and -3 and my y interceps are 0 and 36? i thought the remainder being 0 would be the y-intercept for -2 and -3
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