Question

Which of the following represents the graph of f(x) = 2x + 2? i will give a medal if you help cooperatively

Answer 1

you dont have a graph? using the y=mx+b formula m=2 and b=2

Answer 2

here you go

Answer 3

None of those are f(x) = 2x+2! f(x) = 2x + 2 is a straight line.

Answer 4

I got the same thing that's why I had to question it

Answer 5

well, look carefully at the equation, it's 2^x + 2, not 2x + 2

Answer 6

so let's compute a few values of f(x) and see which graph has them all on the curve.

if x = 0, f(x) = f(0) = 2^0 + 2 =

Answer 7

how would I graph this?

Answer 8

its the last one

Answer 9

x^2 look at it again thats why i couldn't fiqure it out

Answer 10

how do you know because I dont want guessing
this is critical

Answer 11

let's work through this. I asked you a question:

if x=0, f(x) = f(0) = 2^0 + 2 =

what is the number that goes after the final equals sign?

Answer 12

@binks it isn't x^2, it's 2^x

Answer 13

f(x) = 2^x + 2 typo sorry

Answer 14

f(x) = 2^x + 2

Answer 15

@jedi3000 follow along with the steps I give you and you'll know exactly how to do it and be 100% confident in your answer.

Answer 16

alright

Answer 17

so, for the last time,

if x=0, f(x) = f(0) = 2^0 + 2 =

what is the number that goes after the final equals sign?

Answer 18

3 goes after the equal sign

Answer 19

What transformation has changed the parent function f(x) = 3(2)x to its new appearance shown in the graph below?

Answer 20

that graph I sent you was for the other question sorry

Answer 21

right, 2^0 + 2 = 1 + 2= 3, so at x = 0, y = f(x) = f(0) = 3

now let's find the value of the curve at x = 1
f(x) = f(1) = 2^1 + 2 =

and at x = 2:
f(x) = f(2) = 2^2 + 2 =

there should be only one graph that has those points

Answer 22

f(x) = 3(2)^x

you can't just type the symbols you see, you have to add other symbols as necessary to indicate how the symbols are positioned!

3(2)x is NOT the same as 3(2)^x

Answer 23

we go about this pretty much the same way as graphing that other equation.

pick a couple of points, x = 0 is almost always a good one, and so is x = 1. find the value of the function at those points.

f(x) = f(0) = 3(2)^0 = 3*2^0 = 3*1 = 3
f(x) = f(1) = 3(2)^1 = 3*2^1 = 3*2 = 6
f(x) = f(2) = 3(2)^2 = 3*2^2 = 3*4 = 12

Answer 24

Next, we plot those points and see if we can recognize how the curve has been shifted. Here we have 2 basic transformations to choose from:

f(x) + 2 and f(x) + 4 both shift the curve up (subtracting a value from f(x) would shift it down)

f(x+2) and f(x+4) both shift the curve sideways. A feature of the curve previously found at x = 0 now happens at x = -2 or x = -4, shifting the curve to the left. f(x-2) or f(x-4) would shift it to the right.

Answer 25

you can also have a combination (though none of the answer choices here are a combination). f(x-1) + 2 shifts the graph of f(x) right 1 unit and up 2 units, for example.

Answer 26

I got f(x) − 2 for the second problem

Answer 27

For the first prob the answer I put the last one

Answer 28

I am not sure if I am correct though.... :-/