The tables below show solutions for two linear equations. If the two equations make up a system of linear equations, in which quadrant is the solution? Quadrant one Quadrant two Quadrant three Quadrant four
FAN AND MEDAL :)
If they're linear and you're given several points, you can find the equation of each function by using the formula y=m(x-p)+q.
You can then create a system of equations by making the two y values equal to one another, I'm guessing.
The sol'n then should allow you to figure out some values and assign the values a quadrant accordingly. I think that's how you approach this problem.
??
are you able to find the equation of each line?
me? no, I dont really understand what she said...
how about the slope? are you able to find that?
um, no... i'm not really good at this sort of thing
y=mx+b, m is the slope. D:
are you familiar with the slope formula m = (y2 - y1)/(x2 - x1) ??
no, i never learned the formulas for this
for the first table, pick two points and tell me which points you picked
-7 and 3
so that's one point (-7,3) what's another?
-10 and 9
(-10,9) is another point
All points are of the form (x,y)
So the point (-7,3) means x = -7 and y = 3 The point (-10,9) means x =-10 and y = 9
yup.
hold, on im going to try now
ok
i got quadrant 1
What did you get for the slope?
linear
you should have gotten a number for the slope
We have a system of equations. If there's a solution, it's where the lines represented by those equations intersect. Plot the points given, draw a straight line through them. Observe where they intersect.
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