Question

@timo86m
Help me study!

Answer 1

what is the q?

Answer 2

make a system of linear inequalities :)

Answer 3

How?

Answer 4

x+y+z=5000
z=900
y>z
x>y


that is your system :)

Answer 5

aaaahhhhhT_T

Answer 6

i am not 100% sure but you have to solve for x :)

Answer 7

So if I plug z in it would be x+y+900=5000
Nd I would have to find x nd y?

Answer 8

lets back track a bit you know how i got


x+y+z=5000
z=900
y>z
x>y


RIGHT?

Answer 9

Yea.....

Answer 10

then lets reduce it more by plugging in
x+y=4100 <- we simplified and took out 900
y>900
x>y

Answer 11

Ok.... I'm following....

Answer 12

the q askes
what is the least number of votes that candidate x could have received?

Answer 13

So we need to subtract?

Answer 14

yes i am thinking tho

x>y>900

wee need to solve for

x+y=4100 :) we pic y as 901 and now we solve



x+901=4100


Think about it z had 900 and the next highest number is 901 so we need to use that. Cuzz half votes or quarter votes dont count :)

Answer 15

but we not done yet tho :)

Answer 16

cuzz that would be the max
However we can use the max to solve for min. Maybe my way took an extra step but it got us there.

Answer 17

U_U ok.

Answer 18

x+901=4100 x=3199 would be max :) but they want min

Answer 19

So we have to convert it .....to minutes right?

Answer 20

to to minimum :)

Answer 21

hold on gotta go get a pizza

Answer 22

Ok......I'm waiting ......hurry...lol^_^

Answer 23

Jk...........take ur time:)

Answer 24

not to butt in, but can't you spit it in half and add 1

Answer 25

@satellite73 what do u mean?

Answer 26

you have 900 votes accounted for leaving 4100
you want the LEAST amount for the highest vote getter

Answer 27

half of 4100 is 2050 so if they both got 2050 they would have the same total
but if one had 2049 and the other had 2051 then that is the smallest the winner could have

Answer 28

i.e. if X had less than 2051 then it would not be more than candidate Y

Answer 29

Whatt I understand.......ur saying is to divide each and subtract one?

Answer 30

x>y>900 x+y=4100, the smallest number x can be is 2051, satellite is right

Answer 31

so you have 4100 and you need to divide it so that the largest part is as small as possible:

at 2051<2049 x (which is 2051) is as small as it can be while still satisfying the inequality.

Answer 32

I mean 2051>2049

Answer 33

Jus making sure......u divide by 2 from 4100, right?

Answer 34

The possibilities go from 4099>1 to 4098>2 to 4097>3 ... and so on, the object being to count all the way down until the leading number is as small as possible

Answer 35

How did u get the smallest number?

Answer 36

if you keep counting from where I left off you will eventually get to 2051>2049, and if you go past that the inequality no longer works (2050>2050 is false because 2050 is not greater than 2050, they are equal)

Answer 37

Ok thnx for your explanation:)

Answer 38

You're welcome.

Answer 39

So the answer is 2051

Answer 40

yep