Question

Proving Identities:

Answer 1

question?

Answer 2

sin x cos x (cot x + tan x) = 1

Answer 3

distribute the sinxcosx

Answer 4

sincos(cotx+tanx) = sincoscot+sincostan
now, ill show you the first part and you do the second
sincoscot = sincoscos/(sin) = cos^2

Answer 5

now do the same thing with sincostan and remember sin^2+cos^2=1

Answer 6

:O so for the sinxcosx cosx/sinx the sinx should cancel
sinxcosx sinx/cosx the cosx should cancel.

Answer 7

latex and draw doesn't work :/ so it would be a mess

Answer 8

it does work... ^^ it's another identity .

Answer 9

sin^2x +cos^2x = 1
1 on the left 1 on the right
1=1

Answer 10

wait, i thought you can only work on one side of the equation?

Answer 11

yeah I've been working on the left the entire time

Answer 12

sin x cos x (cot x + tan x) is the left side right?
distribute the sinxcosx
something should cancel out

Answer 13

oh i see.

Answer 14

and then you're left with a simple trig identity.

Answer 15

there must be an echo in here

Answer 16

sin^2x + cos^2x = 1 that's another trig identity.

so that becomes 1 on the left side.
1=1

Answer 17

Is the question already solved ??

Answer 18

I think I did solve it

Answer 19

I will twiddla it for clarification

Answer 20

http://www.twiddla.com/1469723

Answer 21

i got it. thanks!

Answer 22

It wasn't closed; so I thought I should ask :)