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OpenStudy (moongazer):
can you use trigonometric substitution in this?
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OpenStudy (unklerhaukus):
What is this?
OpenStudy (moongazer):
sorry, I mean this
OpenStudy (moongazer):
integral sign dx/(9-x^2)
OpenStudy (moongazer):
I tried trigonometric substitution
a^2 - u^2 : Let u = a sin (theta)
but, I get different result when I use partial fractions
OpenStudy (moongazer):
@UnkleRhaukus
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OpenStudy (moongazer):
additional question:
based from my book, it is used with radicals in the form of
OpenStudy (moongazer):
Sqrt(a^2 - u^2)
Sqrt(a^2 + u^2)
Sqrt(u^2 - a^2)
but why is it my teacher said that I should use trig substitution in this:
dx/(x^2 +1)^2
OpenStudy (unklerhaukus):
this looks like a tricky integral , i cannot remember how to do this,
do you have some working?
OpenStudy (moongazer):
which one?
OpenStudy (moongazer):
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OpenStudy (unklerhaukus):
@TuringTest
OpenStudy (turingtest):
you want to solve
integral dx/(x^2 +1)^2
with a trig sub?
OpenStudy (unklerhaukus):
i think we were trying to do
∫dx/(9-x^2) first,
OpenStudy (turingtest):
just factor out the 9 first
OpenStudy (turingtest):
(1/9)∫dx/(1-(x/3)^2)
sin(t)=x/3
...
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OpenStudy (turingtest):
dx=3cos(t)dt
do I need to continue?
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