Differential equations? Calculus? solve the differential equation. f"(s) = sin x, f'(0)=1, f(0)=6
do you mean f"(x)?
yes sorry
Good morning, VBG! Something seems not quite right here. If f ' (x)=sin x and f ' (0), that appears to be two different definitions. Am I correct in supposing you meant f '' (x) = sin x?
Assuming that It's f ' '(x) that equals sin x, then f ' (x) = -cos x +C and f '(0) = 1 = -cos 0 + C. Make sense?
(laplace method is more fun)
Surely is. Vilbarguen is currently offline.
i hadn't thought of applying those initial conditions mid-way (so-to-speak) through solving, i usually wait till the end, but i see that will work fine and even make the method simpler
Hey guys. Sorry I had to leave. yes it is f '' (x), i just used " so I guess it looked like ' .
mathmale so f ' (x) = -cos x +C because it is the antiderivative yes?
Yes, i was confused there. But that's not your fault. Integrate f ' ' (x) and add the constant of integration, C. Find C, based upon the initial conditions.
Your f ' (x" is fine. Can you now find C? I know you must be working on that right now.
so if f ' (0)= 1, I use - cos (0) + C = -1 + C = -1 + 2 f'(0) = 1
am I right?
You are saying that C=2, right? If so, then take your f '(x)=-cos x +2 and integrate every term with respect to x. Add another constant of integration, D.
hold on I don't understand. this is to solve f(0)=6 ?
VBG: You are to integrate your expression for f ' (x), adding a new constant, D, at the end. Once you've done that, you take the last initial condition and insert those values into your f(x). Here's what that would look like: f(0)=6=-sin 0 +2(0) +D. Find D. then write
f(x) = ???? incorporating C=2 and D = ? and then you're done.
f(0)= 6= -sin (0) + 2 (0) + D = 0 + 0 + D=6 f(0) = 6
thats it
So, f(x) = ???
VBG: Please summarize your result: f(x) = ?? If you're tied up with something else, or prefer not to do this, please just say so.
so f(x) = -sin (x) + 2(x) + D ?
sorry about the delay
D= 6 and C= 2 for f'(x)
Yes, and y ou've found that D=6 so you end up with f(x)=-sin x +2x +6, right? You could check this by differentiating, if you want to. Any other concerns related to this homework problem?
ah ok so I put 6 instead of D. got it.
No mathmale thats it. Thank you so much for your help
You're very welcome. De nada. Hope to "meet" with you on OpenStudy again soon. Great day to you. Bye.
Certainly. Thanks again!
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